The first derivative simply explained

Often feared but important in school: learn here how to understand and safely calculate the instantaneous rate of change!

Explanation

Definition

The first derivative of a function f describes the instantaneous rate of change of f and is denoted by f'. The derivative f' indicates how steep the graph of f is at a given point.

The slope between two points P(x_1\,|\,y_1) and P(x_2\,|\,y_2) is calculated with \frac{y_2 - y_1}{x_2 - x_1}. Since f' is the slope of the graph of f at one (and not two) points, the distance between the points in the formula is allowed to approach zero. This gives us the definition of the derivative f':

f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

Procedure

Scheme

To determine the instantaneous rate of change, you differentiate the function using the differentiation rules. The most important differentiation rules are:

f'(x) = n \cdot x^{n-1}

1. Power rule: f(x) = x^n \Rightarrow f'(x) = n \cdot x^{n-1}

2. Constant factor rule: f(x) = c \cdot g(x) \Rightarrow f'(x) = c \cdot g'(x)

3. Sum rule: f(x) = g(x) + h(x) \Rightarrow f'(x) = g'(x) + h'(x)

Examples

Differentiate the function f(x) = 4x^3.

f'(x) = 12x^2

(Power rule applied)

Differentiate the function f(x) = 5x^2 - 3x + 7.

f'(x) = 10x - 3

(Power and sum rule applied)

Note

Summary
  • The first derivative describes the instantaneous rate of change and the slope of a function.
  • Use differentiation rules (power, constant factor, and sum rule) to differentiate graphs.

Exercises

1 / 3
Differentiate the function
f(x) = x^4
2 / 3
Determine the first derivative of
f(x) = 2x^3 - 4x^2 + x
3 / 3
Calculate the first derivative of the function
f(x) = \tfrac{1}{2}x^4 - 3x^3 + 5x - 9
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