Extremum points simply explained

Extremum points are often required in school and seem complicated. Read this article and learn how to calculate them confidently!

Explanation

Definition

Extremum points are special points of a function where the slope 0 is zero. There, the function has either a maximum or a minimum. To find extremum points, you first set the first derivative of the function equal to 0 and then check with the second derivative or the sign change whether it is a maximum or minimum. The fundamental formula for calculating extremum points is:

Formula for calculating extremum points:

f'(x) = 0

with a sign change

Procedure

Scheme

To calculate extremum points, follow these steps:

1. Take the first derivative of the function.

2. Set the first derivative equal to 0 and solve for x solve.

3. Take the second derivative and substitute the found x-values.

4. If the second derivative is positive, there is a minimum. If it is negative, there is a maximum. Alternatively, you can also examine the sign change of the first derivative.

f''(x) > 0 \Rightarrow \text{Minimum}; \quad f''(x) < 0 \Rightarrow \text{Maximum}

Examples

Determine the extremum points of the function f(x) = x^2.

1. Derivative: f'(x) = 2x. Set f'(x) = 0x = 0.

2. Derivative: f''(x) = 2. Since f''(0) = 2 > 0, lies at x = 0 a minimum. The minimum is (0\,|\,0).

Determine the extremum points of the function f(x) = x^3 - 3x.

1. f'(x) = 3x^2 - 3 = 0 \Rightarrow x_1 = 1,\, x_2 = -1.

2. f''(x) = 6x. f''(1) = 6 > 0Minimum at x = 1. f''(-1) = -6 < 0Maximum at x = -1. Minimum (1\,|\,-2), Maximum (-1\,|\,2).

Note

Summary
  • Extremum points are points where the slope 0 is.
  • The second derivative or the sign change of the first derivative shows whether there is a maximum or minimum.

Exercises

1 / 2
Determine the extremum points of the function
f(x) = x^2 - 4x + 3
2 / 2
Determine the extremum points of the function
f(x) = x^3 - 6x^2 + 9x
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